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Lee Corbin wrote:

*> equations "ab - cd = 1" or "a^2 + b^2 = c^2 + 1". I worry
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*> that the first may not even be possible---
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Oh by the way, ab - cd = 1 also has infinitely many solutions:

where a = b and c = a-1 and d = a+1, a,b,c,d all integers, then

ab - cd = a^2 - (a-1)(a+1)= a^2 - (a^2 -1) = 1.

spike

**Next message:**Dale Johnstone: "Re: "analog computer" = useless hypothesis?"**Previous message:**hal@finney.org: "Re: MATH/COMP/PHIL: "Omega Man""**In reply to:**Lee Corbin: "Re: MATH/COMP/PHIL: "Omega Man""**Next in thread:**Mikael Johansson: "Hungarian names (was: Re: MATH/COMP/PHIL: "Omega Man")"**Messages sorted by:**[ date ] [ thread ] [ subject ] [ author ]

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